Question

Find the point on y-axis which is equidistant from the point (5, - 2) and (-3,2).

Answer 1

Step-by-step explanation:

let the point be : P(x,y)

P is equidistant from (5,-2) & (-3,2).

that is, [5+(-3)]÷2= x

[-2+2]÷2=y

or, x=1 and y=0

then the point is P(1,0)