Question

find the point on y axis which is equidistant from the point A(6,5) and B(-4,3)​

Answer 1

HA(6,5) and B(-4,3) yes the answer is a A=11 B_1

Answer 2

The point on y axis which is equidistant from the point A(6,5) and B(-4,3) is (0,9).

Steps:

we know that a point on the y axis is the form of (0,y)

let the point p(0,y)be equidistant from A and B

The  point is said to be equidistant from a set of objects if the distances between that a point and each object in the set are equal.

(6-0)²+(5-y)² = (-4-0)²+(3-y)² then

(6)²+(5-y)²=(-4)²+(3-y)²

36+25+y²-10y = 16+9+y²-6y

4y=36

y=36/4

36 is divided by 4 is equal to 9

y=9

• The required point is (0,9).

• (0,9) is the intersection of the y axis .