Question

find the point where the graph of the linear equation 7 - 2x + 4y= 0 cuts the y-axis

Answer 1

Hiii. ....friend

The answer is here,

=> 7-2x+4y=0.

To find the y intercept , we have to convert the linear equation into slope-intercept form (y =mx+c).

=> 4y =2x-7.

=> y= 2/4x-7/4.

So, If we compare this eq. with y=mx+c.

We get, c=7/4.

So, The linear equation 7-2x+4y =0 cuts the y-axis at (0,7/4)

:-)Hope it helps u.

Answer 2

Answer :

Given:

find the point where the graph of the linear equation 7 - 2x + 4y= 0 cuts the y-axis

=> 7 - 2x + 4y = 0

=> y = mx + c

=> 4y = 2x - 7

=> 4 = 2 / 4x - 7 / 4

=> y = mx + c

=> c = 7 / 4

=> 7 = 2x + 4y = 0

=> [ 0, 7/4 ] = y - axis.