Question

Find the point where the line x−1/2=y−2/−3=z+3/4 meets the plane 2x+4y−z+1=0. ​

Answer 1

Answer:

We have line,

3

x−1

=

4

y+2

=

−2

z−3

=λ............(1)

General point P on the line is,

P=(3λ+1,4λ−2,−2λ+3)

since line (1) intersect plane 2x−y+3z−1=0,

Assume it intersects at a point P

Therefore,

2(3λ+1)−(4λ−2)+3(−2λ+3)−1=0

6λ+2−4λ+2−6λ+9−1=0

4λ=12

λ=3

Therefore ,

P=(10,10,−3))

Option (B) is correct.