Question

Find the point which divides the line segment joining (-1,2),(4,-5) in the ratio 3:2​

Answer 1

Step-by-step explanation:

(-1,2)=(X1,y1)

(4,-5)=(X2,y2)

m1:m2=3:2.

Section formula:

$p(x \: y) = (\frac{m1x2 + m2x1}{m1 + m2} \: \frac{m1y2 + m2y1}{m1 + m2} )$

=> [ 3×4+2×(-1)/2+3. 3×(-5)+2×2/2+3[

=> [12-2/5. -15+4/5]

=> [10/5, -11/5]

=> [2, -11/5].

Answer 2

x1, y1 = (-1, 2)

x2, Y2= (4, -5)

m1:m2=3:2

section formulae = (m1x2+m2x1/m1+m2, m1y2+m2y1/m1+m2)

=(3×4+2×-1/1/2+3 , 3×-5+2×2/2+3)

=(12-2/5, -15+4/5)

=(10/5, -11/5)

(2,-11/5)