Question

find the point which is equal distance from the point p(1,2) Q(-4,6)​

Answer 1

Answer:

by the distance formula = √(x2-x1)^2 +(y2-y1)^2

PQ = √((-4-1)^2 + (6-2 )^2

PQ = √(25 +16 )

PQ = √ 41 units .

the answer is√41 units , I hope to you are like my answer thank you.