Find the point whose ordinate is equal to the abscissa and which is equidistant from (0, 4) & (2, 0).
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Heya Mate!!
Here's your answer!!
Since the abscissa and the ordinate of a point are equal, let the co - ordinates of the points be P(x,x)
Since it is equidistant from the points A(0, 4) and B(2, 0),
PA² = PB²
=> (0 - x)² + (4 - x)² = (2 - x)² + (0 - x)²
=> x² + 16 - 8x + x² = 4 - 4x + x² + x²
=> 16 - 8x = 4 - 4x
=> 8x - 4x = 16 - 4
=> 4x = 12
=> x = 3
Therefore the co - ordinates of the points are (3, 3).
Hope it helps you!!
Cheers :D
#foreverJungkook
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