Question

Find the points on the X-axis which is equidistant from (2,-5) and (-2,9)​

Answer 1

Answer:

The point is (-7,0) which is equidistant from (2,-5) and (-2,9).

The point is on the x axis. Hence we can assume the coordinate of the point as (h,0).

Now the point is equidistant from (2,-5) and (-2,9).

So (2-h)^{2} + (-5)^{2} = (h+2)^{2} + (-9)^{2}(2−h)

2

+(−5)

2

=(h+2)

2

+(−9)

2

Simplifying this we get -4h + 29 = 4h + 85−4h+29=4h+85

Or 8h = -56 or h= -7

Hence the point is (-7,0) which is equidistant from (2,-5) and (-2,9).

I hope this answer helpful for you