find the points on the y axis whose distances from (3,2) and ( -1,3/2) are in the ratio 2:1.
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Point on Yaxis A(0, b) , C (-1, 3/2)
B (3, 2)
AB=under root (3-0) ^2+ (2-b) ^2
AC =under root (-1-0) ^2+ (3/2-b) ^2
AB /AC=2:1
AB^2/AC^2=4:1
3+ (2-b) ^2= 4 ((1+ (3/2-b) ^2)
by solving this we get b=13/4
So point on yaxis be (0, 13/4)
B (3, 2)
AB=under root (3-0) ^2+ (2-b) ^2
AC =under root (-1-0) ^2+ (3/2-b) ^2
AB /AC=2:1
AB^2/AC^2=4:1
3+ (2-b) ^2= 4 ((1+ (3/2-b) ^2)
by solving this we get b=13/4
So point on yaxis be (0, 13/4)
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