Question

find the points on x axis which is equidistant from points - 2, - 5 and 2, - 3

Answer 1

Hi ,

Let P ( x , 0 ) is a point which is equidistant

from A( -2 , - 5 ) and B ( 2 , -3 ) .

Now ,

AP = BP

AP² = BP²

[ x - ( -2 ) ]² + [ 0 - ( - 5 ) ]² = (x - 2)² + [0 - ( - 3 )]²

( x + 2 )² + 5² = ( x - 2 )² + 3²

x² + 4x + 4 + 25 = x² - 4x + 4 + 9

4x + 29 = -4x + 13

4x + 4x = 13 - 29

8x = -16

x = -16/8

x = -2

Therefore ,

Required number = ( x , 0 ) = ( -2 , 0 )

I hope this helps you.

: )