find the points on y-axis which is equidistance from the points - 5 ,- 2 and 3 2.
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Answered by
13
point on y-axis x=0
point=(0,y)
equidistant from (5,-2) and(-3,2)
distance from first point=(25+y^2+y-4y)^1/2
distance from second point=(9+y^2+4-4y)^1/2
both equals
squaring both
29+y^2+4y=13+y^2-4y
8y=-16
y=-2
point=(0,-2)
point=(0,y)
equidistant from (5,-2) and(-3,2)
distance from first point=(25+y^2+y-4y)^1/2
distance from second point=(9+y^2+4-4y)^1/2
both equals
squaring both
29+y^2+4y=13+y^2-4y
8y=-16
y=-2
point=(0,-2)
Answered by
6
-2and 2is the y axis point
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