Find the points which are equidistant from the points P(-3,0) and Q(3,0) using the Cartesian plane. How many such points are possible?
Answers
Answered by
0
Answer:
don't know but please mark me as brainlist
Answered by
1
Answer:
5
Step-by-step explanation:
Given,
PA=PB
(PA)
2
= (PB)
2
So by distance formula we have,
Distance between two points =
(x
2
−x
1
)
2
+(y
2
−y
1
)
2
⇒ (x−7)
2
+(3+1)
2
= (x−6)
2
+(3−8)
2
⇒ x
2
+49−14x+16 = x
2
+36−12x+25
⇒ 49+16−36−25=2x
⇒ 65−61=2x
⇒ x=4
Distance:
AP=
(4−7)
2
+(−1−3)
2
(by distance formula)
=
(3)
2
+16
=
9+16
=
2
5
=5
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