Question

Find the points which are equidistant from the points P(-3,0) and Q(3,0) using the Cartesian plane. How many such points are possible?

Answer 1

Answer:

don't know but please mark me as brainlist

Answer 2

Answer:

5

Step-by-step explanation:

Given,

PA=PB

(PA)

2

= (PB)

2

So by distance formula we have,

Distance between two points =

(x

2

−x

1

)

2

+(y

2

−y

1

)

2

⇒ (x−7)

2

+(3+1)

2

= (x−6)

2

+(3−8)

2

⇒ x

2

+49−14x+16 = x

2

+36−12x+25

⇒ 49+16−36−25=2x

⇒ 65−61=2x

⇒ x=4

Distance:

AP=

(4−7)

2

+(−1−3)

2

(by distance formula)

=

(3)

2

+16

=

9+16

=

2

5

=5