Question

Find the polar form of Z= -3√2+3√2i

Answer 1

Answer:Z=6(cos 3π/4+i sin 3π/4)

Step-by-step explanation:

Z= -3√2+3√2i

then,|z|=√{(-3√2)²+(3√2)²}

|z|=√{18+18}

|z|=√36

|z|=6

tan α=tan| 3√2/-3√2 |

tan α=tan| -1 |

tan α=tan| π/4 |

α=π/4

As, Z is in II Quadrant then, ∅=π-α

∅=3π/4

Z= |z|(cos∅+i sin∅)

=>Z=6(cos 3π/4+i sin 3π/4)

Answer 2

Answer:

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