Question

. Find the polar of (3,-1) with respect to 2x²+2y²= 11.
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Answer 1

Answer:

polar of the point (x1,y1) with respect to the circle 2x² + 2y² = 11 is given by 2xx1 + 2yy1 = 11

substituting the point (3,-1) into the equation give

2x(4) + 2y(-1) = i.e. 8x – 2y = 11 is the required polar.

Answer 2

Answer:

2x²+2y²=11

2(x x1) + 2(y y1)=11

2x.3 + 2y.-1 =11

6x-2y-11=0