Find the polynomal whose zeros are rute 5 and _ rute 5
Answers
Answered by
1
Sum of zeroes = 5 - 5 = 02
Product of zeroes = 5(-5) = -25
Required polynomial = x^2 -(sum of zeroes)x + Product of zeroes
= x^2 - (0)x + ( -25)
= x^2 -25
Product of zeroes = 5(-5) = -25
Required polynomial = x^2 -(sum of zeroes)x + Product of zeroes
= x^2 - (0)x + ( -25)
= x^2 -25
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Answered by
15
Heya !!
Let Alpha = √5 and Beta = -√5.
Sum of zeroes = Alpha + Beta = √5 - √5 = 0
And,
Product of zeroes = Alpha × Beta = √5 × -√5 = -5.
Therefore,
Required quadratic polynomial = X²-(Sum of zeroes)X + Product of zeroes.
=> X² - (0) X + (-5)
=> X² - 5
Let Alpha = √5 and Beta = -√5.
Sum of zeroes = Alpha + Beta = √5 - √5 = 0
And,
Product of zeroes = Alpha × Beta = √5 × -√5 = -5.
Therefore,
Required quadratic polynomial = X²-(Sum of zeroes)X + Product of zeroes.
=> X² - (0) X + (-5)
=> X² - 5
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