Find the polynomial whose zeroes are 2,1&-1.what is its degree
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we know that no. of zeroes =its degree
∴its degree is 3 and its cubic polynomial
α+β+Δ=2 , αβ+βΔ+Δα=1 , αβΔ= -1
=k[ x³ - (α+β+Δ) x² + (αβ+βΔ+Δα) x - αβΔ ]
=k[ x³-2x²+1.x-(-1)]
=k(x³-2x²+x+1)
here k = 1
∴its degree is 3 and its cubic polynomial
α+β+Δ=2 , αβ+βΔ+Δα=1 , αβΔ= -1
=k[ x³ - (α+β+Δ) x² + (αβ+βΔ+Δα) x - αβΔ ]
=k[ x³-2x²+1.x-(-1)]
=k(x³-2x²+x+1)
here k = 1
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