find the polynomial whose zeroes are √3/2 and -√3/2
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9
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kaur193:
hey mate u done something wrong the correct answer of this ques is x^2-3/2 not that answer which u find and ur answer is x^2-3/4
Bro/sis see the product of zeroes other one has done √3/2×(-√3/2)= -3/4 not 3/2
mine is correct
Answered by
14
alpha= √3/1
beta = -√3/2
sum of zero = alpha + beta
=√3/2 +{-√3/2}
= √3/2-√3/2
=0
product of zero = Alpha × beta
= √3/2 ×{-√3/2}
=-3/2
Q P = K ( x²-Sx+ P)
0/k = x² - 0x + [-3/2]
0 = x²-3/2
0×2 = 2x²-3
0= 2x²-3
beta = -√3/2
sum of zero = alpha + beta
=√3/2 +{-√3/2}
= √3/2-√3/2
=0
product of zero = Alpha × beta
= √3/2 ×{-√3/2}
=-3/2
Q P = K ( x²-Sx+ P)
0/k = x² - 0x + [-3/2]
0 = x²-3/2
0×2 = 2x²-3
0= 2x²-3
Ludhiana
yeah
Bro see the product of zeroes you have done √3/2×(-√3/2)= -3/4 not 3/2
kya
oh sorry i thought it was only on 3
its the fault of asker they need right answer but they do not give focki[ng right question
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