Question

find the polynomial whose zeroes are given:alpha=2 and beta=3​

Answer 1

Answer:

Re

Step-by-step explanation:

$reed \: equation \\ {x }^{2} - ( \alpha + \beta )x + \alpha \beta = 0 \\ as \: \alpha = 2 \: \: \beta = 3 \\ \alpha + \beta = 2 + 3 = 5 \\ \alpha \beta = 2 \times 3 = 6 \\ {x}^{2} - 5 {x}^{2} + 6x = 0$