Find the polynomial whose zeros are 5 root 19 , 5-root19
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zeroes of polynomial= a+b=-b/a=5rt19/1
a×b=c/a=5-rt19/a
so a=1,b=5rt19,c=5-rt19
so the polynomial are in a form ax2+bx+c=0
so ans is=1x2+5rt19x+(5-rt19)=0
hope this may help u
a×b=c/a=5-rt19/a
so a=1,b=5rt19,c=5-rt19
so the polynomial are in a form ax2+bx+c=0
so ans is=1x2+5rt19x+(5-rt19)=0
hope this may help u
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