Question

find the polynomial whose zeros are 9 and 1/9

Answer 1

α+β=-b/a

αβ = c/a

9+1/9 =81+1/9= 82/9

9 x 1/9 =9/9 =1

k(x²-(α+β)x + αβ)

k (x²-(82/9)x+1)

k[(9x²-82/9x+1/9)/9]

if k =9

polynomial is 9x²-82x+1.....

Answer 2

Answer:

Step-by-step explanation:

X ^2-1/9x+9x+1=x^2-82/9x+1=9x^2-82x+9=0