Question

Find the polynomial with the zeros 21/8 and 5/16

Answer 1

Given:- the roots of equation
are 21/8 & 5/16


Sum of zeros


$= \frac{21}{8} + \frac{5}{16}$


$= \frac{42 + 5}{16}$



$= \frac{47}{16}$


Product of zeros

$= \frac{21}{8} \times \frac{5}{16}$


$= \frac{105}{128}$

⭐To form the quadratic equation we have formula

=>
${x}^{2} - (sum \: of \: zeros)x + (products \: of \: zeros)$

=>putting the values in formula

we get,

${x}^{2} - ( \frac{47}{16} )x + ( \frac{105}{128} ) = 0$


$\frac{128 {x}^{2} - 376x + 105}{128} = 0$

=>128x²-376x+105 is the required quadratic equation.

@Altaf