Question

find the position and magnification of the image of an object placed at a distance of 8cm in front of a convex lens of focal length 10cm.

Answer 1

position of image is -40cm

magnification is +5

Answer 2

Given that,

Object distance, u = -8 cm

Focal length of the convex lens, f = +10 cm

To find,

The position and magnification of the image.

Solution,

Let v is the position of formed image. Using lens formula to find it as :

$\dfrac{1}{f}=\dfrac{1}{v}-\dfrac{1}{u}\\\\\dfrac{1}{v}=\dfrac{1}{f}+\dfrac{1}{u}\\\\\dfrac{1}{v}=\dfrac{1}{10}+\dfrac{1}{(-8)}\\\\v=-40\ cm$

Magnification,

$m=\dfrac{v}{u}\\\\m=\dfrac{-40}{-8}\\\\m=5$

So, the position of image is at (-40 cm) and magnification is 5.

Learn more,

Lens formula

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