find the position nature and size of the image of an object 3 cm height placed at a distance of 9 cm from a concave mirror of focal length 18 cm
Answers
the given spherical mirror is a concave mirror and the object is placed 3 cm height from the principal Axis so due to the sign convention it remains positive therefore ho=3cm
and the next part of the question makes understand that the object is placed 9 CM from the concave mirror. due to sign convention the measurement becomes negative therefore object distance, u=- 9 CM
and also the focal length of a concave mirror is to be taken negative due to the sign convention f=-18cm
so here we know the values of height of the object ,object distance and focal length
we know the formula , 1\f=1\v+1\u
1\-18=1\v+1\-9
6-3\-54=1\v
v=-18 cm
the magnification of the image can be found by using the formula - v\u
m,=-(-18)\-9
=18\-9
=-2
as the magnification of the mirror is -2 the image is real and inverted as the magnification number is more than 1 the image is magnified.
therefore the size of the image is more than that of the size of the object
and given mirror forms a real inverted and magnified image
Answer:
The answer is -2 ,which is the real and magnified