Question

Find the position of centre of buoyancy for a wooden block of width 3.5 m and depth 1 m, when it floats horizontally in water. The density of wooden block id 850 kg/m3 and its length 7.0 m.

Answer 1

0.85 m will be the position of centre of buoyancy for a wooden block of width 3.5 m and depth 1 m, when it floats horizontally in water. The density of wooden block id 850 kg/m3 and its length 7.0 m.

Explanation:

Weight  of the block= m g = ρ* volume    .................. eq 1

as mass = density * volume

using above formula in eq 1 and equating values :

taking value of g = 9.81

ρ*g*Volume=850*9.81*7*3.5*1=204.29 kN

Volume of  water displaced=  ($\frac{Weight of water displaced/weight density of water}{weight density of water}$

= 20.825 m3.

h= volume / area

= 20.825/3.5*7=0.85 m.

Answer 2

Answer:

0.85 m

Explanation:

Weight of the block=ρ*g*Volume=850*9.81*7*3.5*1=204.29 kN

Volume of

water displaced= Weight of water displaced/weight density of water

= 20.825 m3.

h=20.825/3.5*7=0.85 m.