Find the position,size and nature of image formed by a spherical mirror from the following data:
Focal length= - 12 cm
Object distance= - 36 cm
Size of object= 2 cm
Answers
Answered by
53
Nature of image:Real and inverted
position:
1/v+1/u=1/f
=>v=-18cm
size:
m= height of image/height of object=-v/u
=> height of image =-1
therefore diminished
position:
1/v+1/u=1/f
=>v=-18cm
size:
m= height of image/height of object=-v/u
=> height of image =-1
therefore diminished
pritpalchahal19:
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Answered by
76
Position of the image
1/v=1/f-1/u
Therefore 1/v= -1/12 - (-1/36)
=-1/12 + 1/36
Take LCM
=-3+1/36
=-2/36
=-1/18
Therefore v=-18
Nature of image:---Real and Inverted
Size of image
h2/h1=-v/u
h2/2=-(-18/-36)
h2/2=-(18/36)
h2=-18*2/36
h2=-1
1/v=1/f-1/u
Therefore 1/v= -1/12 - (-1/36)
=-1/12 + 1/36
Take LCM
=-3+1/36
=-2/36
=-1/18
Therefore v=-18
Nature of image:---Real and Inverted
Size of image
h2/h1=-v/u
h2/2=-(-18/-36)
h2/2=-(18/36)
h2=-18*2/36
h2=-1
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