Question

find the positive root of √3xsquare+6=9
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Answer 1

Answer:here is your answer Mark brainlist plzSqrt ( 3x^2 + 6 ) = 9

Sqrt ( 3x^2 + 6 ) = 9Do the square bothsides of the

Sqrt ( 3x^2 + 6 ) = 9Do the square bothsides of theEquation.

Sqrt ( 3x^2 + 6 ) = 9Do the square bothsides of theEquation.3x^2 + 6 = 81

Sqrt ( 3x^2 + 6 ) = 9Do the square bothsides of theEquation.3x^2 + 6 = 813x^2 = 81 - 6

Sqrt ( 3x^2 + 6 ) = 9Do the square bothsides of theEquation.3x^2 + 6 = 813x^2 = 81 - 63x^2 = 75

Sqrt ( 3x^2 + 6 ) = 9Do the square bothsides of theEquation.3x^2 + 6 = 813x^2 = 81 - 63x^2 = 75Divide bothsides with 3

Sqrt ( 3x^2 + 6 ) = 9Do the square bothsides of theEquation.3x^2 + 6 = 813x^2 = 81 - 63x^2 = 75Divide bothsides with 33x^2 / 3 = 75/ 3

Sqrt ( 3x^2 + 6 ) = 9Do the square bothsides of theEquation.3x^2 + 6 = 813x^2 = 81 - 63x^2 = 75Divide bothsides with 33x^2 / 3 = 75/ 3x^2 = 25

Sqrt ( 3x^2 + 6 ) = 9Do the square bothsides of theEquation.3x^2 + 6 = 813x^2 = 81 - 63x^2 = 75Divide bothsides with 33x^2 / 3 = 75/ 3x^2 = 25Now ,

Sqrt ( 3x^2 + 6 ) = 9Do the square bothsides of theEquation.3x^2 + 6 = 813x^2 = 81 - 63x^2 = 75Divide bothsides with 33x^2 / 3 = 75/ 3x^2 = 25Now ,x = sqrt ( 25 )

Sqrt ( 3x^2 + 6 ) = 9Do the square bothsides of theEquation.3x^2 + 6 = 813x^2 = 81 - 63x^2 = 75Divide bothsides with 33x^2 / 3 = 75/ 3x^2 = 25Now ,x = sqrt ( 25 )x = + or - 5

Sqrt ( 3x^2 + 6 ) = 9Do the square bothsides of theEquation.3x^2 + 6 = 813x^2 = 81 - 63x^2 = 75Divide bothsides with 33x^2 / 3 = 75/ 3x^2 = 25Now ,x = sqrt ( 25 )x = + or - 5But we need pisitive root ,

Sqrt ( 3x^2 + 6 ) = 9Do the square bothsides of theEquation.3x^2 + 6 = 813x^2 = 81 - 63x^2 = 75Divide bothsides with 33x^2 / 3 = 75/ 3x^2 = 25Now ,x = sqrt ( 25 )x = + or - 5But we need pisitive root ,therefore ,

Sqrt ( 3x^2 + 6 ) = 9Do the square bothsides of theEquation.3x^2 + 6 = 813x^2 = 81 - 63x^2 = 75Divide bothsides with 33x^2 / 3 = 75/ 3x^2 = 25Now ,x = sqrt ( 25 )x = + or - 5But we need pisitive root ,therefore ,x = 5

Answer 2

Step-by-step explanation:

root and square cancel to give 3x+6=9;3x=3;x=1