Question

Find the positive value of k for which the equation 2x square +kx+2=0 has real roots

Answer 1

Step-by-step explanation:

2x^2+kx+2=0

D= b^2-4ac

= k^2-4*2*2

=k^2-16

For real roots

D=0

k^2-16=0

k^2 =0+16

k^2=16

k =+_√16

k=+_4