Question

Find the positive value of the variable for which the given equation is satisfied ​

Answer 1

Answer:

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Answer 2

Answer:

$\frac{y {}^{2} + 6}{8y {}^{2} + 3} = \frac{1}{5}$

$1(8y {}^{2} + 3) = 5(y {}^{2} + 6)$

8y²+3=5y²+30

8y²-5y²= 30-3

3y²=27

y²=

$\frac{27}{3}$

y²=9

y=3