Question

find the positive value of z if 3z^2+7/4+x^2=2​

Answer 1

Answer:

Z=1

Step-by-step explanation:

3z²+7/4+x²=2

3z²+7=2x²+8

let X=1

3z²=3

z²=1

z=√1

z=1

Answer 2

Answer:

BY CROSS MULTIPLICATION:

3z^2+7=2(4+z^2)

3z^2+7=8+2z^2

3z^2-2z^2=8-7

z^2=1

z=√1

z=1

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