Find the possibility of getting ace of hearts and ace of spades from 52 cards.
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6
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So the probability of drawing a heart first and then an ace is the sum of the probabilities of the 3 events. Sum of events 1,2,3 is 51(52)(51)=152 So this is the probability of drawing a head first and then an ace...
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Step-by-step explanation:
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Answered by
31
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Here's Your Answer
Step-by-step explanation:
If A: { getting at least a spade and ace}, then Ac : {getting no spade or ace}. Now, in a deck there are 52 cards of which 13 are spades and remaining 39 cards are non-spades (clubs,hearts and diamonds). And these 39 cards include 3 aces of three suits.
Now, total number of ways in which 2 cards can be drawn from the deck is C(52,2) and the number of ways in which these 2 cards are drawn from 36 (=52–13–3) cards is C(36,2) . Hence, P(Ac)=C(36,2)C(52,2)=105221
- So, the required probability P(A)=1−P(Ac)=1−105221=116221
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