Question

Find the possible values of constant k if the roots are x^2-(k+2)x +4=0 are equal

Answer 1

Answer:

K = -6 and 2

Step-by-step explanation:

x² - (k + 2)x + 4 = 0

If zeroes are equal then ,

Discriminant (D) = 0

b² - 4ac = 0

(k + 2)² - 4*1*4 = 0

k² + 4 + 4k - 16 = 0

k² + 4k - 12 = 0

k² + 6k - 2k - 12 = 0

k (k + 6) - 2 (k + 6) = 0

(k + 6) (k - 2) = 0

K = -6 and 2

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