find the potential difference between the two terminals of a conductor if 25 of work is moving 2 micro coulomb of electric charge
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Answer:
50×10^-6C
Explanation:
1 micro coulomb = 1×10^-6 C
2 micro coulomb = 2×10 ^-6 C
Potential difference = PE×Q
Potential difference =25× 2×10^-6
Potential difference =50×10^-6
Potential difference = 50 × 10^-6 C
JAI SHREE KRISHNA
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v=w/q
v=w/qv=100/20
v=w/qv=100/20v=5
v=w/qv=100/20v=5
Hope this help
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