Question

Find the Power of the enginedeployed to lift water at the rate of 5 litre of water in one
second through an average height of 10m from a well of depth 10m assume 10percent of power of engine is wasted

Answer 1

power=work done/time taken

time taken=1 sec

power=work done

work=mgh

h=10+10

=20 m

g=10

mass=density*volume

=5 kg

work=5*20*10

=1000

now 90% of total power is 1000 J

therefore total power is 10000/9

=1111.11 J