Find the power of the vehicle of mass 5×10^5 kg rising on an inclined plane of inclination 1 in 100 with a constant speed of 60km/hr and the frictional force between wheels and surface is 23.992×103N
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Answer:
From FBD,
F=mgsinθ+f
or F=mg
x
h
+f as(sinθ=
x
h
)
or Fx=mgh+fx
or W
F
=mgh+W
f
as work done = force × distance.
150=5×10×2+W
f
or W
f
=150−100=50J
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