Question

find the power required to life 10 kg of coal per hour from a mine 360m deep in​

Answer 1

Hey there!

Mistakes in the question!

Question will be ---->

Calculate the power of an engine required to lift 100000 kg of coal per hour from a mine 360m deep.

Answer----->

Mass(m) = 100000 kg = 10^5 kg

Height (h) = 360m

Acceleration due to gravity = 10 m/s^2

Time(t) = 1 hour = 3600 s

Then,

P.E = mgh

     = 10^5 * 10 * 360 J

Work done = P.E = 10^5 * 10 * 360 J

We know,

Power = Work done / Time

           = 10^5 x 10 x 360/3600

           = 10^5 watt.

Hope It Helps You!

plz mark as brainliest