Question

Find the power supplied by different sources using kcl kvl equation in the following given circuits show in figure

Answer 1

Answer:

Mesh 1:-2I  

1

​

+2(I  

1

​

+I  

2

​

)=6v

⟹4I  

1

​

−2I  

2

​

=6v

⟹2I  

1

​

−I  

2

​

=3→(1)

Mesh 2:-4I  

2

​

+2(I  

1

​

+I  

2

​

)=2v

⟹6I  

2

​

−2I  

1

​

=2→(2)

Equating (2) and (1)

I  

2

​

=1A

I  

1

​

=2A

Explanation: