Find the Present Ages of Father and Son
The present age of the father is four times the age of his son. Four years later he will be three times the age of his son. Find their present ages?
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the age of father is 32 and that of son is 8.
father age = x
son age = y
x = 4y => x - 4y = 0 ........(1)
x+4 = 3(y + 4) => x+4 = 3y + 12 => x - 3y - 8 = 0 .......(2)
by elimination , we get y = 8
so x = 4y = 4*8 = 32
hence proved.
father age = x
son age = y
x = 4y => x - 4y = 0 ........(1)
x+4 = 3(y + 4) => x+4 = 3y + 12 => x - 3y - 8 = 0 .......(2)
by elimination , we get y = 8
so x = 4y = 4*8 = 32
hence proved.
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