Question

Find the pressure 200m below the surface of the ocean of pressure on the free surface of liquid is one atmosphere (density of sea water =1060)
(Pls do ans it right pls

Answer 1

ANSWER:

21.789x 10^5 N/m²

Explanation:

h:- 200m

p:- 1060kg/m³

g:- 9.8m/s²

Patm:- 1.013x10 N/m2

FORMULA:

P=Po+hpg

= 1.013x10 + 200 x 1060x 9.8

= 21.789x 10^5 N/m²

Answer 2

Complete question:

Find the pressure 200 m below the surface of the ocean if the specific gravity of sea water is 1.03.

[Atmospheric pressure = 1.013 × 10⁵ N/m²]

Answer:

The value of pressure 200 m below the ocean's surface is 20.613 × 10⁵ N/m²

Explanation:

The pressure at depth is given as:

P = P₀ + Pₐ

Where,

P₀ = Atmospheric pressure = 1.013 × 10⁵ N/m²

Pₐ = Gauge pressure = ρgh

On substituting the values, we get,

P = (1.013 × 10⁵) + ρgh

Where,

ρ = Density of water = 1000 kg/m³

g = Acceleration due to gravity = 9.8 m/s²

h = Height where the pressure is need to be found = 200 m

On substituting the values, we get,

P = (1.013 × 10⁵) + (1000 × 9.8 × 200)

P = (1.013 × 10⁵) + 1960000 = (1.013 × 10⁵) + (19.6 × 10⁵)

∴ P = 20.613 × 10⁵ N/m²