Find the pressure exerted at the tip of the drawing pin ,if it is push on a boat with a force of 20 Newton and area of the tip to be 0.1 mm^2.
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As-Salamu-Alykum
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Force = 20N
Area = 0.1mm^2
1mm^2=(1/10cm )^2
So....
0.1mm^2 = (1/10×0.1)^2
0.1mm^2 = 1/100×0.01
0.1mm^2 = 10^_4cm^2
1cm^2 = (1/100m)^2
10^_4cm^2= (1/100)^2 ×10^_4
10^_4cm^2 = 10^_8m^2
P =?
P=F/A
P = 20/10^_8
P= 20×10^8Pascal
__________
INSHALLAH it will help U
____________
Force = 20N
Area = 0.1mm^2
1mm^2=(1/10cm )^2
So....
0.1mm^2 = (1/10×0.1)^2
0.1mm^2 = 1/100×0.01
0.1mm^2 = 10^_4cm^2
1cm^2 = (1/100m)^2
10^_4cm^2= (1/100)^2 ×10^_4
10^_4cm^2 = 10^_8m^2
P =?
P=F/A
P = 20/10^_8
P= 20×10^8Pascal
__________
INSHALLAH it will help U
ish30181551:
what step u have written after o.1mm^2=1/100×0.01
plz tell
and also tell me solution of another 3 question I asked
plz help me
1/100 means 10^_2 and there is another 10^_2 So this becomes equal to 10^_4
why u had putted underscore_
and plz tell me another 3 solutions for the question I asked
plz ... plz.... plz.... help me ...
it is 1/10^2 but in numerator its sign will change it will become 10^_2
ohh ! ok thanku.....☺☺
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