Physics, asked by Ruthviks2390, 10 months ago

Find the pressure exerted by a cube kept on a table with a side of 100cm and mass 10kg

Answers

Answered by prakashroy1211
1

Formulas used : Preassure = Force ÷ Area

Area of a cube = 6a^2, where a is the side.

Force = mass × axceleration

In this question, Force = mass × acceleration due to gravity(g)

SI units of mass is kg, Force is Newton(N), Area is m^-2, Preassure is Nm^-2 or Pa.

In this situation,

area of the cube = 6 × (100 × 10^-2)^2

=6×1

=6m^2

Force = 10 × 9.8

= 98N

Preassure = 98÷6

=16.334Nm^-2 or Pa

Hope the answer is clear for you.

[THANK YOU]

Answered by raj3294
1

Answer:

Explanation:

SIDE OF THE CUBE=100 CM

                                 = 1 M                      [ TO CONVERT CM TO M MULTIPLY      

                                                                           BY 10^-2 OR DIVIDE BY 100]

MASS = 10 KG

PRESSURE= FORCE/ AREA

                  =M G /AREA                         [ SINCE ONLY ONE SIDE OF THE

                                                                  CUBE IS IN CONTACT WITH THE

                                                                  TABLE TOP ONLY AREA OF THAT  

                                                                  ONE SIDE IS CONSIDERED]

PRESSURE=10*9.8/1*1

                  = 98 PASCAL.

HOPE THIS HELPS.

Similar questions