Find the pressure exerted by a cube kept on a table with a side of 100cm and mass 10kg
Answers
Formulas used : Preassure = Force ÷ Area
Area of a cube = 6a^2, where a is the side.
Force = mass × axceleration
In this question, Force = mass × acceleration due to gravity(g)
SI units of mass is kg, Force is Newton(N), Area is m^-2, Preassure is Nm^-2 or Pa.
In this situation,
area of the cube = 6 × (100 × 10^-2)^2
=6×1
=6m^2
Force = 10 × 9.8
= 98N
Preassure = 98÷6
=16.334Nm^-2 or Pa
Hope the answer is clear for you.
[THANK YOU]
Answer:
Explanation:
SIDE OF THE CUBE=100 CM
= 1 M [ TO CONVERT CM TO M MULTIPLY
BY 10^-2 OR DIVIDE BY 100]
MASS = 10 KG
PRESSURE= FORCE/ AREA
=M G /AREA [ SINCE ONLY ONE SIDE OF THE
CUBE IS IN CONTACT WITH THE
TABLE TOP ONLY AREA OF THAT
ONE SIDE IS CONSIDERED]
PRESSURE=10*9.8/1*1
= 98 PASCAL.
HOPE THIS HELPS.