Find the pressure exerted by the solid cylinder of weight 20kg
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Answer:
A solid cylinder of mass 20Kg has length 1m and radius 0.2m. Then its moment of inertia (inkg−m 2 ) about its geometrical axis is-
I=20*0.2*0.2/2=0.4kgm^2.
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Answer:
hy dude ur answer is
Explanation:
Given
A solid cylinder has weight 20kg
Length=1m
and also radius is 0.2m
Here, moment of inertia is ( in kg
(-m2)
Therefore, Length is 20×0.2/2=0.4 kgm^2
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