Question

Write a quadratic equation whose roots are 3and 4

Answer 1

Answer: (x^ 2 )-7x+12=0

Step-by-step explanation:quadratic equation is (x^2) - (a+b)x + ab = 0

Where a and b are zeros or roots of the quadratic equation

Answer 2

Step by step explanation:

Given roots of an quadratic equation and 3/4 ans 4/3

Sum of roots$= \frac{3}{2} + \frac{4}{3} = \frac{9 + 8}{6} = \frac{17}{6}$

Products of roots$= \frac{3}{2} \times \frac{4}{3} = 2$

So, equation of quadratic equation is as,

$x {}^{2} - (Sum \: of \: roots)x + (Product \: of \: root \: ) = 0 \\ = {x}^{2} - ( \frac{17}{6} )x + 2 = 0 \\ = {6x}^{2} - 17x + 12 = 0$

Hence, quadratic equation is

${6x}^{2} - 17x + 12 = 0$