Math, asked by mamtalohia89, 26 days ago

Find the prime factorisation of the following number: i) 8020

Answers

Answered by paarishasingh
2

Answer:

2 x 2 x 5 x 401

Step-by-step explanation:

Let's start by dividing 8,020 by 2

8,020 ÷ 2 = 4,010 - No remainder! 2 is one of the factors!

4,010 ÷ 2 = 2,005 - No remainder! 2 is one of the factors!

2,005 ÷ 2 = 1,002.5 - There is a remainder. We can't divide by 2 evenly anymore. Let's try the next prime number

2,005 ÷ 3 = 668.3333 - This has a remainder. 3 is not a factor.

2,005 ÷ 5 = 401 - No remainder! 5 is one of the factors!

401 ÷ 5 = 80.2 - There is a remainder. We can't divide by 5 evenly anymore. Let's try the next prime number

401 ÷ 7 = 57.2857 - This has a remainder. 7 is not a factor.

401 ÷ 11 = 36.4545 - This has a remainder. 11 is not a factor.

401 ÷ 13 = 30.8462 - This has a remainder. 13 is not a factor.

If we put all of it together we have the factors 2 x 2 x 5 x 401 = 8,020.

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