Math, asked by rajnaitik010, 27 days ago

find the prime factorization of 256 and 3125 by division method class 6​

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Answered by 12784
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Answer:

The factors of 256 are integers that divide 256 without any remainder.

Let's learn how to calculate factors of 256.

Let's begin calculating the factors of 256, starting with 1.

256 ÷  1 = 256, Remainder = 0

256 ÷  2 = 128, Remainder = 0

256 ÷ 4 = 64, Remainder = 0

256 ÷ 8 = 34, Remainder = 0

256 ÷ 16  = 16 Remainder = 0

All the divisors and the quotient thus obtained on division form the factors of 256. They are: 1, 2, 4, 8, 16, 32, 64, 128 and 256.

Hence, the factors of 256 are 1, 2, 4, 8, 16, 32, 64, 128 and 256.

All Factors of 3125: 1, 5, 25, 125, 625 and 3125

Negative Factors of 3125: -1, -5, -25, -125, -625 and -3125

Prime Factors of 3125: 5  

Prime Factorization of 3125: 5^5

Sum of Factors of 3125: 3906

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