Question

Find the principal amount( P ) for the following cases. a). r = 4.5 %, n = 5 years I = 250 . SOLUTION .​

Answer 1

Answer:

Given :-

• A simple interest is Rs 250, rate of interest is 4.5% and time period is 5 years.

To Find :-

• What is the principal amount.

Formula Used :-

$\clubsuit$ Principal Formula :

$\bigstar \: \: \sf\boxed{\bold{\pink{P =\: \dfrac{S.I \times 100}{R \times T}}}}\: \: \: \bigstar$

where,

• P = Pressure
• S.I. = Simple Interest
• R = Rate of Interest
• T = Time Period

Solution :-

Given :

• Rate of Interest = 4.5%
• Time Period = 5 years
• Simple Interest = Rs 250

According to the question by using the formula we get,

$\implies \sf\bold{\blue{P =\: \dfrac{S.I \times 100}{R \times T}}}$

$\implies \sf P =\: \dfrac{250 \times 100}{4.5 \times 5}$

$\implies \sf P =\: \dfrac{25000}{22.5}$

$\implies \sf\bold{\red{P =\: Rs\: 1111.11}}$

$\sf\bold{\purple{\underline{\therefore\: The\: principal\: (P)\: is\: Rs\: 1111.11\: .}}}$

Answer 2

Answer:

If  r = 4.5 %, n = 5 years I = 250, then the principal amount( P )  is 1111.11 Rs.

Step-by-step explanation:

Given: Rate (r) = 4.5 %

Time (N) = 5 years

Simple Interest (I) = 250 Rs

Find the principal amount( P )

Formula: $I=\frac{PNR}{100}$

Put the values in formula

$250=\frac{P\times 5 \times 4.5}{100}\\ P\times 5 \times 4.5 = 250 \times 100\\22.5 P= 25000\\P = 25000 \div 22.5\\P = 1111.11$

So, the principal amount( P )  is 1111.11 Rs.