Question

find the principal argument of z = 6(cos310° - i sin310°)​

Answer 1

Answer:

5π/18

Step-by-step explanation:

Given: z = 6(cos 310° - i sin 310°)

              = 6[cos(360° - 50°) - i sin(360° - 50°)]

∴ cos(360 - θ) = cosθ and sin(360 - θ) = -sinθ

              = 6(cos 50° + i sin 50°)

              = 6(cos 5π/18 + i sin 5π/18)

Thus, Principal argument = 5π/18.

Hope it helps!

Answer 2

6[cos(360° – 50°) – i sin(360° – 50°)]

= 6(cos 50° + i sin 50°)

= 6(cos `(5pi)/18 ` + i sin `(5pi)/18` )