Question

Find the principal if Simple Interest = 1560, T = 5 1/5 years and R = 12 % p.a​

Answer 1

Answer:

Solution

P = Rs 1500, R = 12% p.a., T = 3 years

∴SI=  

100

PRT =  100

1500×12×3

​

=Rs540

∴ Amount = P + SI = Rs 2040

Step-by-step explanation:

Answer 2

$\large{\underline{\underline{\maltese{\pink{\pmb{\sf{ \; Given \; :- }}}}}}}$

• ➯ Simple Interest = ₹1560
• ➯ Time = $\sf{5 \frac{1}{5} }$ years
• ➯ Rate = 12% per annum

__________________________________________

$\large{\underline{\underline{\maltese{\green{\pmb{\sf{ \; To \: Find\; :- }}}}}}}$

• Principal = ?

__________________________________________

$\large{\underline{\underline{\maltese{\red{\pmb{\sf{ \; Solution\; :- }}}}}}}$

❒ Formula Used :

• Principal

$\purple{\bigstar} \: \: \: \small{\underline{{\boxed{\sf{\pink{P = \frac{100 ×I}{R × T} }}}}}}$

Where :

• ➢ P = Principal
• ➢ I = Simple Interest
• ➢ R = Rate
• ➢ T = Time

ㅤㅤㅤ ____________________________

❒ Calculating the Principal :

${⟹} \: \: \bf{\red{P = \frac{100 \times I}{R × T} }}$

$⟹ \sf \: \: { P = \frac{100 \times \cancel{1560} \: ^{\cancel{60} } \: ^{5} \times 5}{\cancel{12} \: ^{1}× \cancel{26} \: ^{1}} }$

$⟹ \: \: \: \sf{P = ₹(100 × 5 × 5)}$

$⟹ \: \: \: \sf\green{P = ₹2500}$

$\bf \pink{∴ The \: required \: Principal \: is \: ₹2500.}$

ㅤㅤㅤ ____________________________

$\large{\underline{\underline{\maltese{\purple{\pmb{\sf{ \; Additional \: Formulas\; :- }}}}}}}$

• Simple Interest

$\sf{⇝ \: \: \frac{Principal × rate × time}{100} } = \frac{P×R×T}{100}$

• Rate of Interest

$\sf{⇝ \: \: \frac{100×Interest}{Principal × Time} = \frac{100×I}{P×T} }$

• Time

$\sf{⇝ \: \: \frac{100×Interest}{Principal × Rate} = \frac{100×I}{P×R} }$

• Amount

$\sf{⇝ \: \: Principal + Interest =P(1 + \frac{R × T}{100} )}$

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