Question

find the principal if the compound interest at the rate of 10% per annum for 2 years is rupees 1250

Answer 1

a=p(1+r/100)^n
1250=p(1+10/100)^2
1250=p(100+10/100)^2
1250=p×100/100×10/100
1250=p×10
1260=10p
1250/10=p
125=p
ci=a-p
=1000-125
=875
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