Find the principal, if the compound interest (compounded annually) at the rate of 10% per annum for three years is ₹331.
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good question but is is already here
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Answered by
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Answer:
P = Rs. 1000
Step-by-step explanation:
let P be the principal
r = 10% , n = 3
A = A = P(1 + r / 100) ^n
interest for 3 yrs is rs. 331
⇒ P ( 1 + r/100 )^n - P= I, I is the C.I
⇒ P (1 + 10/100 )^3 - P = 331
⇒ P [ ( 1 + 1 /10 )^3 -1 ] = 331
⇒ P [ (10 +1 /10)^3 - 1] = 331
⇒P [ (11/10)^3 - 1 ] = 331
P (1.331 - 1) = 331
P [ 0.331 ] = 331
P = 331 / 0.331
P = Rs. 1000
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