Two parallel rail tracks run north-south. Train a moves due north with a speed of 54 km h-1 and train b moves due south with a speed of 90 km h-1. What is the relative velocity of b with respect to a in m s-1?
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Answer:
The relative velocity of b with respect to a is 40 m/s
Explanation:
Train a moves to north with the speed say s(a)= 54 km /h
Train b moves to south with the speed say s(b)= 90 km /h
Therefore the relative velocity of b with respect to a=
s(b)-s(a)
= -90-54
= 144 km/h
now to convert km/h to m/s
144km/h x 1000m/1 km x 1 h/3600s
= 40 m /s
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